Chemical Forums
Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: metallurgy on June 16, 2020, 03:57:56 AM
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How to prepare Sodium Tetraborate Solutions?
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Dissolve a solid compound in water.
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Dissolve a solid compound in water.
According to literature the tetraborates should be 0.09-0.68 %(w.) of metallurgical coke and 3g./L. density,
So shall I dissolve 9-68g. solid sodium tetraborates in 100mL. of pure water and then discharge into spray-flasks and eject onto 10kg. of metallurgical coke?
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Sodium tetraborate (borax) can be anhydrous, pentahydrate, or decahydrate. You must make sure which chemical your description applies to. In addition, borax dissolves poorly in water. To dissolve the maximum amount you will need about 1 to 2 liters of water depending on the temperature.
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Sodium tetraborate (borax) can be anhydrous, pentahydrate, or decahydrate. You must make sure which chemical your description applies to. In addition, borax dissolves poorly in water. To dissolve the maximum amount you will need about 1 to 2 liters of water depending on the temperature.
Decahydrate.
And room temperature.
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Solubility about 30 g/L
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Solubility about 30 g/L
But in literature they've shown 3-5-7-10 g. /L , the why?
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What literature? The temperature is missing.
The solubility of an anhydrous substance - 13, 16, 27, 39 g/L at 0, 10, 20, 30°C, respectively. For decahydrate - 1.895 times more.
Your data concern probably solubility of decahydrate in 100 g water at an unidentified temperature - my guess 10, 30, ~90, 100°C.
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What literature? The temperature is missing.
The solubility of an anhydrous substance - 13, 16, 27, 39 g/L at 0, 10, 20, 30°C, respectively. For decahydrate - 1.895 times more.
Your data concern probably solubility of decahydrate in 100 g water at an unidentified temperature - my guess 10, 30, ~90, 100°C.
In this patent:
It shows 3-10g/L.
https://patents.google.com/patent/RU2539186C1/en
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The patent clearly informs us that numbers concern anhydrous borate but hydrates are used.
A solution (or suspension of calcium tetraborate) containing 3 to 10 g of anhydrous borate in an amount sufficient to obtain a content of 0.2 to 0.5% borate in coke is used. The English text is a faithful translation of the original Russian patent.
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The patent clearly informs us that numbers concern anhydrous borate but hydrates are used.
A solution (or suspension of calcium tetraborate) containing 3 to 10 g of anhydrous borate in an amount sufficient to obtain a content of 0.2 to 0.5% borate in coke is used. The English text is a faithful translation of the original Russian patent.
if we use 0.5%(w.) of borate for 10 kg. coke then we need to use 50 g. borate and 1-2 litres pure water, right?
Or in order to prepare 5g./L density , we need to use 10-20 litres pure water?
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Yes, 10 L of water. But the coke temperature is 1050 +- 50°C.
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Yes, 10 L of water. But the coke temperature is 1050 +- 50°C.
So? What coke temperature does if its that high?
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Try to estimate. Coke cooling, according this patent, lasts 90-120 seconds.
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Try to estimate. Coke cooling, according this patent, lasts 90-120 seconds.
Is the litres of solution changes when it comes to 1100C temp.?