Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: kamehamehaaa on September 24, 2006, 10:33:11 PM

Hello can someone help me calculate the mass of Cu(NO_{3})_{2}3H_{2}O needed to prepare 50.0mL of a .50 M Cu(II) solution?
I would appreciate it if you can help me through this problem by telling me what I should do rather than give me the answer.
Thanks

Do you know how to figure out what the molar mass of Cu(NO_{3})_{2}*3H_{2}O is?

Yeah I got the molar mass to be 241.599 grams, but I don't know how to set it up from there.

i'm not sure if i'm right :\ . but i think first of all , you would have to write a balanced chemical equation .from that you can figure it out. i think so. :P

Yeah I got the molar mass to be 241.599 grams, but I don't know how to set it up from there.
How would you go from here in the case of Cu(NO_{3})_{2}?

The molar mass would be 241.599 g/mol

Yeah I got the molar mass to be 241.599 grams, but I don't know how to set it up from there.
When Copper (II) Nitrate dissolves, how many moles of Cu^{2+} are released per mole of Cu(NO_{3})_{2}?