Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: xshadow on October 01, 2020, 09:29:23 AM
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Hi
Here I have the steps for this reaction:
(https://i.imgur.com/vIMlFpE.jpg)
I have a doubt:
Why does pyridine deprotonate tue -CH2- group instead of -COOH
I've checked and the pka are:
-COOH ≈ 3.75/4.74
-CH2- (between the COOH groups) ≈ 12
The pyridine should deprotonate the fsr more acidic COOH groups ??? ???
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I am also wondering, normally Malonicesters are used. But its a modification of Knoevenagel reaction. All acidic H+ will be removed by pyridin, see link.
https://illumina-chemie.de/viewtopic.php?t=4791
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I think the last eliminationstep is catalyzed by acid and therefore the weak pyridine as base and the malonic acid rather than malonic ester is used. Even if pyridine is a weak base there will be some of the malonic CH2-groups deprotonated, its a equilibrium.
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I think the last eliminationstep is catalyzed by acid and therefore the weak pyridine as base and the malonic acid rather than malonic ester is used. Even if pyridine is a weak base there will be some of the malonic CH2-groups deprotonated, its a equilibrium.
The small amount of malonic molecules with the CH2- group deprotonated also has the COOH group deprotonated?
Or it can be some molecule with the -COOH not deprotonated but CH2 deprootnated?
Thanks
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Yes, the COOH will also be deprotonated.
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As seen in the link I posted before.
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Thankss!!
:)