Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: ComradeLenin on November 16, 2020, 01:10:52 PM
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While doing some hybrid orbitals exercises, i found this exercise. I'll try to give a literal and clear translation, let me know if something is not clear. The excercise: "The bond angles of 107° of ammonia can be explained assuming that the central Nitrogen atom has sp3 hybridization. If they used p pure orbitals when forming bonds, what would be the size of the H-N-H bond angles?". The problem here is that I haven't even understood what they mean, can someone help me?
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Meaning, if the s orbitals on the three hydrogen atoms bonded only to three p-orbitals on nitrogen, what would the molecular shape be in terms of the H-N-H angles?
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Meaning, if the s orbitals on the three hydrogen atoms bonded only to three p-orbitals on nitrogen, what would the molecular shape be in terms of the H-N-H angles?
Thank you very much!