# Chemical Forums

## General Forums => Generic Discussion => Topic started by: Win,odd Dhamnekar on February 03, 2021, 08:14:31 AM

Title: Hydroformylation of Olefins
Post by: Win,odd Dhamnekar on February 03, 2021, 08:14:31 AM
Hydroformylation of olefins yields aldehydes which further undergo reduction to give alcohols.

$$H_2 + CO +RCH = CH_2 \rightarrow RCH_2CH_2CHO \tag{1}$$

$$H_2 + RCH_2CH_2CHO \rightarrow RCH_2CH_2CH_2OH \tag{2}$$

What is R in the reaction(1)?

The product doesn't seem to look alcoholin reaction (2). What is R in reaction (2)?
Title: Re: Hydroformylation of Olefins
Post by: AWK on February 03, 2021, 08:59:47 AM
The hydroformylation process is exceptionally well developed in technology textbooks, on the internet, and even on Wikipedia. You only need to read.
Depending on the reaction conditions, the product may be formate esters (not methyl ethers).
Title: Re: Hydroformylation of Olefins
Post by: Orcio_87 on March 06, 2021, 02:58:08 PM
"R" in reaction 1 and 2 is simply the rest of molecule which is not important for reaction. It can be alkyl (-CH3, -CH2CH3) or aryl (-C6H5 - fenyl group) group or something else.