Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Monoamine on March 21, 2021, 05:45:00 PM
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Hi, so I have a compound which contains both OH and tertiary amine. Basically I am hoping to homologate the OH to a methoxy group by a Williamson ether synthesis, The problem is that this would also alkylate the amine, producing ammonium cations. Naturally I would prefer to avoid this
I attached a schematic with the proposed synthesis. If anyone would be willing to share what the right protective group mighty be here, and how the are added and removed again. I would be very grateful to know.
Cheers.
Ps: Suppose you want to go the other way around, and cleave the methoxy into a OH group. Could you apply the same procedure, where instead you use HBr to cleave the ether? (again by protecting the amine?
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Why not use the opposit. Use instead of the Aminephenol the Bromine compound and alkylate with Methylate sodium CH3O- Na+
Or reduce he acetic ester of the Aminephenol by with Triethylsilan Bor triflouride ether
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Can you think of any protecting groups?
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Honestly, methyl iodide, methylate both spots, then in the presence of a decent nucleophile and a little heat, the desired molecule is basically a leaving group.
For instance, if you stir the dimethylated compound with a large excess of KCl, the chloride will attack a methyl on the amine via SN2 and you'll produce some methyl chloride and the desired product.