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Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: lukas.stib on March 26, 2021, 07:31:52 PM

Title: How much of ZnCl2 for the synthesis of 1,3-dichloropropane?
Post by: lukas.stib on March 26, 2021, 07:31:52 PM

Hello chemists,

I want to ask you how much anhydrous zinc chloride should I use in Lucas´ reagent for the synthesis of 1,3-dichloropropane from 100 g of 1,3-propanediol and 96 g of HCl according to stoichiometry? Or not use ZnCl2 as catalyst for synthesis of 1,3-dichloropropane? Of course, I know that I will have to convert 96 g HCl to 35% hydrochloric acid.

Thank you, Lukáš S.

Title: Re: How much of ZnCl2 for the synthesis of 1,3-dichloropropane?
Post by: rolnor on March 27, 2021, 07:24:26 AM

You need excess HCl with equimolar ZnCl2,
https://en.wikipedia.org/wiki/Lucas%27_reagent

I dont know if its so good to make primary chlorides?

Title: Re: How much of ZnCl2 for the synthesis of 1,3-dichloropropane?
Post by: lukas.stib on March 27, 2021, 08:57:25 AM

OK, thank you.