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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: j.s_g on May 03, 2021, 03:09:04 PM

Title: Effective nuclear charge
Post by: j.s_g on May 03, 2021, 03:09:04 PM

About the electron that is being analyzed for the effective nuclear charge equation: why is one electron always subtracted from the total numbers of electrons when you are calculating the shielding constant?
I've searched in many sites, but I couldn't understand this...
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Title: Re: Effective nuclear charge
Post by: Orcio_87 on May 03, 2021, 04:27:25 PM

Because shielding is a reduction in proton-electron attraction which a chosen electron receives because of the presence of electrons occupying inner shells.

Title: Re: Effective nuclear charge
Post by: j.s_g on May 03, 2021, 04:39:49 PM

@Orcio_Dojek Got it. Thank you very much!