Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: xshadow on June 03, 2021, 02:03:08 PM
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I have some doubts about what s happen in this multistep synthesis :
(https://i.imgur.com/Jr2I6dp.jpg)
(I only know the reagents of each step.)
After ibx there is "heat" : I don't know if it's right my supposition
I thought that two thing could happen:
A) intramolecular dies alder...but I should get a nine-term ring so I exclude it
B) I imagine that the diene acts as nucleophile and gives an 1,4 addition with the ring closure.
But this addition generates a carbocation and I don't have any nucleophole that can react with it....and in the next step I have an acid hydrolysis.... (that I think could open the lactone/ 1,4 additopn)
Some help??
Thanks :)
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A diene as nucleophile?
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A diene as nucleophile?
is strange...
The only other thing is that a diels alder actually happens but I can't see it
Could I have the formaton of two ring?. or one ring plus a 3 terms"bridge".
(Don't think that nothing happens in this step)
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If you google intramolecular diels-alder you can find various examples. Long-story short, usually they make fused bicycles.
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Can be something like that?
(https://i.imgur.com/VmanE7c.jpg)
Ps: I forgot a double bond on C5-C4
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That looks right. You could also predict relative stereochemistry at carbons 1 and 2, the two stereocenters that originate from the diene, because Diels-Alder maintains the relative stereochemistry of each individual part. Stereochem at carbon 3 is trickier. This carbon would determine whether its an endo product or an exo product, which is often beyond the scope of an introductory class. You could certainly draw two diastereomers and point out which one is endo and which one is exo. But if you are currently in the class, the professor would likely accept an answer where carbon 3 has no stereochemistry indicated.
Edit: In this case, it would actually be difficult to call either of them endo, because the dienophile has two different electron withdrawing groups. So it's especially tricky, maybe just making whichever ring fusion is more stable.
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There is a double bond missing after DA
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There is a double bond missing after DA
yes!
The one between C5-C4
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That looks right. You could also predict relative stereochemistry at carbons 1 and 2, the two stereocenters that originate from the diene, because Diels-Alder maintains the relative stereochemistry of each individual part. Stereochem at carbon 3 is trickier. This carbon would determine whether its an endo product or an exo product, which is often beyond the scope of an introductory class. You could certainly draw two diastereomers and point out which one is endo and which one is exo. But if you are currently in the class, the professor would likely accept an answer where carbon 3 has no stereochemistry indicated.
Edit: In this case, it would actually be difficult to call either of them endo, because the dienophile has two different electron withdrawing groups. So it's especially tricky, maybe just making whichever ring fusion is more stable.
thanks :)
Diastereoselecctvity is a bit tricky in dies alder....the easy part is that If I have cis alkene --> syn product
BUt we haven't done very well the relationship between the alkene and dienophile substituents