Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: emilie on June 10, 2021, 08:43:47 PM
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Hi, I've been working on this chemistry problem for class and I'm not seeing where I'm messing up.
Here's the question:
Chlorine gas reacts with fluorine gas to form chlorine trifluoride.
Cl2(g) + 3 Fs(g) :rarrow: 2 ClF3(g)
A 2.00-L reaction vessel, initially at 298 K, contains chlorine gas at a partial pressure of 337 mmHg and fluorine gas at a partial pressure of 729 mmHg. Identify the limiting reactant and determine the theoretical yield of ClF3 in grams.
Here's what I did:
mol Cl2: PV = nRT
n = PV/RT = (337 mmHg x (1 atm / 760 mmHg) x 2.00 L) / (0.08206 L atm / mol K x 298K) = 0.036266 mol Cl2
mol F2: n = PV/RT = (729 mmHg x (1 atm / 760 mmHg) x 2.00 L) / (0.08206 L atm / mol K x 298 K) = 0.078451 mol F2
Limiting reactant
0.036266 mol Cl2 (3 mol F2 / 1 mol Cl2) = 0.109 mol F2
Limiting reactant is F2 since it's less than the Cl2
Theoretical yield of ClF3
0.078451 mol F2 (2 mol ClF3/3 mol F2)(92.45 g ClF3 / 1 mol F2) = 4.84 g ClF3
And this answer is not correct. What am I not seeing? Thanks!
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Book answer is F2 is limiting reactant and 2.84 g ClF3 is the theoretical yield.
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Your answer looks OK to me, must be an error in the book.