Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: xshadow on June 19, 2021, 11:35:37 AM
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HII!!
Have to balance this redox:
FeS2 + Na2O2 --> Na2SO4 + Na2O + Na2FeO4
First I balanced the Sulfur atom:
FeS2 + Na2O2 --> 2 Na2SO4 + Na2O + Na2FeO4
FeS2 + Na2O2 --> 2 Na2SO4 + Na2O + Na2FeO4
OX1: 2S (-1) ---> 2S (VII) + 14 e-
OX2: Fe(II) ---> Fe (VI) + 4 e-
OX TOT: 18e-
Now I have trouble with the oxygen/ reduction
Because on the left I have Na2O2 with N.O = -1.
On the right I have three oxygen with N.O= -3 and I don't know how to advance.
If I consider only Na2O on the right I get:
FeS2 + Na2O2 --> 2 Na2SO4 + 2Na2O + Na2FeO4 (balanced the oxygen involved in the redox as i done before with Sulfur)
2O (-1) + 2e- --> 2O (-2)
OX TOT : 18 e- X1
RID: 2 e- X9
FeS2 + 9Na2O2 --> 2 Na2SO4 + 18Na2O + Na2FeO4
But doens't work.
Thanks
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OX1: 2S (-1) ---> 2S (VII) + 14 e-
S(VI), but I suppose that's just a typo, as electrons are OK.
On the right I have three oxygen with N.O= -3
Another typo?
If I consider only Na2O on the right I get:
FeS2 + Na2O2 --> 2 Na2SO4 + 2Na2O + Na2FeO4 (balanced the oxygen involved in the redox as i done before with Sulfur)
Not sure what you did here nor why. Oxygen is not balanced.
This is actually easier to balance just by inspection, start with a single FeS2 and see where it leads you.