Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Win,odd Dhamnekar on September 13, 2021, 11:11:00 AM
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Answers to d : 5 moles of Ferrous Oxalate (FeC2O4) are required to reduce 2 moles of Potassium Permanganate in acidic medium
Answer to e: Redox equation is [tex]K_2Cr_2O_7 + 3 Cu_2S + 14 H^+ \rightarrow 6 Cu^{2+} +3 S + 7 H_2O + 2K^+ + 2 Cr[/tex]
From the aforesaid equation, we can say that [itex]\frac56[/itex] moles of K2Cr2O7 is required to react completely with 2.5 moles of Cu2S in acidic medium.
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When using dichromate for oxidation Cr is not reduced to solid metal.
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My answer to a) is wrong. I have two probable answers 1)75 ml of K2Cr2O7.
It is computed as under:
0.3 M = 300 mmol :rarrow:50 ml of 300mmol = 15mmol
So volume of Potassium Dichromate × 0.2 M = 15mmol :rarrow: volume of K2Cr2O7= 75 ml
2) Using this formula v.f.1 × M1 × volume1= v.f.2× M2 × volume2
Plugging in the values available with us into this formula, we have 6×0.2M× V1=2×0.3M × 50 ml
= 25 ml of Potassium Dichromate
Which of the above answer is correct?
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Ignoring hints won't help you.