Chemical Forums

Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: novalia on November 21, 2021, 05:23:43 PM

Title: Calculating Change in Enthalpy via Equation Manipulation
Post by: novalia on November 21, 2021, 05:23:43 PM
I can't seem to wrap my head around this today. Any tips, insight, or otherwise appreciated. Please let me know if you can see the image.
Title: Re: Calculating Change in Enthalpy via Equation Manipulation
Post by: Borek on November 22, 2021, 02:43:35 AM
Image is there, but small and barely readable.

Per forum rules (https://www.chemicalforums.com/index.php?topic=65859.0) you have to show your attempts at answering the question/solving the problem to receive help. But I will give you a hint: reverse the second equation.
Title: Re: Calculating Change in Enthalpy via Equation Manipulation
Post by: Orcio_87 on November 22, 2021, 10:25:23 AM
Quote
I can't seem to wrap my head around this today. Any tips, insight, or otherwise appreciated. Please let me know if you can see the image.
Add equations altogether to get the desired one (N2O + NO2 ---> 3 NO).
Title: Re: Calculating Change in Enthalpy via Equation Manipulation
Post by: novalia on November 30, 2021, 07:26:19 PM
Quote from: Borek on November 22, 2021, 02:43:35 AM
Image is there, but small and barely readable.

Per forum rules (https://www.chemicalforums.com/index.php?topic=65859.0) you have to show your attempts at answering the question/solving the problem to receive help. But I will give you a hint: reverse the second equation.

Hi, thanks for the hint. I reversed the second equation and multiplied by .5, and I multiplied the third equation by .5 as well. I got +155.65 kJ as the ΔH.