Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: yoyohs on December 08, 2021, 02:29:15 PM
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A voltaic cell at 25oC consists of Mn/Mn2+ and Cd/Cd2+ half-cells with the initial concentrations [Mn2+] = 0.100 M and [Cd2+] = 0.0100 M. Use the Nernst equation to calculate E for this cell.
Cd+2(aq) + 2e- = Cd(s) . . . . . . Eo = -0.40 V
Mn+2(aq) + 2e- = Mn(s) . . . . . . . Eo = -1.18 V
this is what i did, but it is wrong. https://drive.google.com/file/d/1HzBRnAl7CzwAbmwGWjE0z1JWF1M2sypu/view?usp=sharing (https://drive.google.com/file/d/1HzBRnAl7CzwAbmwGWjE0z1JWF1M2sypu/view?usp=sharing)
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Write the equation for the spontaneous cell reaction. What is Q?
(Alternatively, work out the modified potentials for each electrode separately, and then combine them.)