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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Isotomatti on January 25, 2022, 10:49:01 PM

Title: Specific Heat Capacity: explanation for How much heat did the metal lose?
Post by: Isotomatti on January 25, 2022, 10:49:01 PM

I know it's (heat energy x -1) but I forgot to write down the explanation and I cannot find it on any corner of the internet. Any ideas? like for example:

Calculate the heat gained by the water in units of joules:
q= m(50.00) x Cp(4.184) x dT(1.90) = 396.7 joules

How much heat did the metal lose? Explain
Heat lost = q x -1 so -396.7 but how?

Title: Re: Specific Heat Capacity: explanation for How much heat did the metal lose?
Post by: Orcio_87 on January 26, 2022, 12:40:35 AM

Here is a good explanation: https://en.wikipedia.org/wiki/First_law_of_thermodynamics

Also - dont write that heat gained is 397 J and heat lost is -397 J because that means that system gained 794 J of energy.

(heat lost is 397 J, without minus sign)