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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: SamanthaMcOw on June 27, 2022, 07:34:29 AM

Title: Buffer preparation calculations
Post by: SamanthaMcOw on June 27, 2022, 07:34:29 AM

Hi Folks!

I would like to know if I am thinking correctly when solving this problem. I have to prepare 80mM ammonium formate (1L volume), MW 63.03 g / mol.

I calculated it this way:

(0,08 M* 1L)/63,03 g/mol= 0,13 g

So I need to weight 0,13 g into 1 L of mili water....is that correct, weight seems a bit low

Title: Re: Buffer preparation calculations
Post by: Aldebaran on June 27, 2022, 10:18:39 AM

I haven’t checked your Mr but assuming it’s correct at 63.03 then you’d need 63.03g per litre for a molar solution. Thus for 0.08 molar you would need ….?

Title: Re: Buffer preparation calculations
Post by: Babcock_Hall on June 27, 2022, 11:22:59 AM

Think about units cancellation.

Title: Re: Buffer preparation calculations
Post by: SamanthaMcOw on June 28, 2022, 04:29:28 AM

Quote from: Aldebaran on June 27, 2022, 10:18:39 AM

I haven’t checked your Mr but assuming it’s correct at 63.03 then you’d need 63.03g per litre for a molar solution. Thus for 0.08 molar you would need ….?

then I will need 5,04 g/L

Is that correct :)?

Title: Re: Buffer preparation calculations
Post by: Borek on June 28, 2022, 06:42:35 AM

Looks OK now.

Title: Re: Buffer preparation calculations
Post by: Aldebaran on June 28, 2022, 11:40:58 AM

Correct!