Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Ion.liq on July 31, 2022, 03:35:07 PM
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Hi everyone,
I need your help... I would like to prepare 3-(Chloromethyl)-2-hydroxybenzaldehyde.
In SciFinder I found a few recipes:
DOI https://doi.org/10.1039/D0NJ03637D (PHOTO 1)
DOI https://doi.org/10.1016/j.fuel.2021.121154 (PHOTO 2)
but on a scheme of reaction (PHOTO 3) is ZnCl2 as a catalyst. In any recipe, ZnCl2 was no included.
I tried with 1:1 molar ratio salicylaldehyde:ZnCl2 and formaline:ZnCl2
The obtained product was 5-(Chloromethyl)-2-hydroxybenzaldehyde or the mixture this two compounds.
Maybe you have some suggestion?
Synthesis of 5-(Chloromethyl)-2-hydroxybenzaldehyde is very simple. I mixed by 48 hours paraformaldehyde, salicylaldehyde and HCl 37% at room temperature. The yield f reaction was above 80%. But sythesis of 3-(Chloromethyl)-2-hydroxybenzaldehyde was difficult. Maybe ZnCl2 as a Lewis acid catalyst is necessary?
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Your reference seems good so you should not need to change anything, just follow the recipe carefully.
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Your reference seems good so you should not need to change anything, just follow the recipe carefully.
but if I followed the recipe (not included ZnCl2) I obtained 5-(Chloromethyl)-2-hydroxybenzaldehyde not 3-(Chloromethyl)-2-hydroxybenzaldehyde
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They have NMR-data in the reference. Its hard to think they have the wrong material. Do you follow the procedure exactly?
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There might be a typo since the protocols doesnt include ZnCl2 unlike the schemes right?
I think the problem lies in the fact that all papers refence a same one:
10.1016/j.tetlet.2006.09.149
which has functional group at the 5 position therefore your reaction cant go there. Maybe try it without ZnCl2 or get 5-bromo salicylaldehyde and after your synthesis hydrogenate it with Pd/C and hydrogen to get rid of the bromine
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They have NMR-data in the reference. Its hard to think they have the wrong material. Do you follow the procedure exactly?
So, tell me what is different in these two synthesis 5-(Chloromethyl)-2-hydroxybenzaldehyde and 3-(Chloromethyl)-2-hydroxybenzaldehyde (temperature?)
5-substituted - https://doi.org/10.1039/B613705A
3- substituted (post 1)
These procedures are the same for me, but they obtained two different compounds.
I prepared 5-(Chloromethyl)-2-hydroxybenzaldehyde using this same procedure, but I used paraformaldehyde, not formaldehyde, HCl, and salicylaldehyde, and NMR spectra of 5-(Chloromethyl)-2-hydroxybenzaldehyde is below
Is it possible to obtain two different compounds using formaldehyde and using paraformaldehyde?
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Nice with some NMR-spektra!
You should follow the procedure EXACTLY, why it did not work can be difficult to say but use the same reagents and try again.
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Those are not so easy to distinguish by simple 1H NMR. The 1,2,3 substituted vs the 1,2,5 - the major differences are the couplings - for 1,2,3 the H in the middle should couple to both adjacent H's and be a double of doublets - but the coupling constants are the same (more or less) so it may look like a triplet. The other two H's couple to the middle one and then weakly to the other - look like doublets of doublets. The 1,2,5 has two H3 and H4 ortho to each other and H6 is para to H3 and meta to H4. H4 should be a real doublet of doublets. H3 and H6 simple doublets - with different coupling constants. (ortho coupling larger than meta, para effectively 0)
The resolution on your NMR is not enough for me to tell here. - but you can probably see it.
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Those are not so easy to distinguish by simple 1H NMR. The 1,2,3 substituted vs the 1,2,5 - the major differences are the couplings - for 1,2,3 the H in the middle should couple to both adjacent H's and be a double of doublets - but the coupling constants are the same (more or less) so it may look like a triplet. The other two H's couple to the middle one and then weakly to the other - look like doublets of doublets. The 1,2,5 has two H3 and H4 ortho to each other and H6 is para to H3 and meta to H4. H4 should be a real doublet of doublets. H3 and H6 simple doublets - with different coupling constants. (ortho coupling larger than meta, para effectively 0)
The resolution on your NMR is not enough for me to tell here. - but you can probably see it.
I analyzed a few publications and supplementary info. I think, that my obtained product is 3-(Chloromethyl)-2-hydroxybenzaldehyde.
All the time I thought, that I obtained 5-substituted product because I made it using preparation for 3-substituted compound.
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That is definitely 1,2,4 subsitution. (yours is numbered 1,2,5 because aldehyde has naming and numbering priority - but as a generic substitution pattern it is 1,2,4).
See it here: https://hatsudy.com/nmr-b.html
If you had 1,2,3 substitution you would not see this pattern. Instead - a fuzzy triplet for H5, and the doublets of doublets for H4 and H6.
ChemDraw will predict it for you - reasonable but not perfect.
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That is definitely 1,2,4 subsitution. (yours is numbered 1,2,5 because aldehyde has naming and numbering priority - but as a generic substitution pattern it is 1,2,4).
See it here: https://hatsudy.com/nmr-b.html
If you had 1,2,3 substitution you would not see this pattern. Instead - a fuzzy triplet for H5, and the doublets of doublets for H4 and H6.
ChemDraw will predict it for you - reasonable but not perfect.
So what I thought at the beginning I have 5-(Chloromethyl)-2-hydroxybenzaldehyde
Now I need to prepare 3-(Chloromethyl)-2-hydroxybenzaldehyde
Thank you all for your help :)
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I wonder if this is correct, two doublets and one double doublett, is that not what you want? Do you have mp?
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I wonder if this is correct, two doublets and one double doublett, is that not what you want? Do you have mp?
I need to prepare 3-(Chloromethyl)-2-hydroxybenzaldehyde (PHOTO1), but all experimental procedures lead to 5-(Chloromethyl)-2-hydroxybenzaldehyde (PHOTO 2)
MP my compounds is 84-86°C (this is mp 5-(Chloromethyl)-2-hydroxybenzaldehyde)
All experimental procedures are almost the same, so still I'm looking...
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Its strange, the nmr, is the doublet at 7ppm cdcl3? They have nmr in your reference, have you checked that? This is a published compound, get proper nmr-data and/or repeat the procedure exactly.
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You can buy the 3-methyl salicylaldehyde commercially - would radical chlorination work (N-chlorosuccinimide and benzoyl peroxide, for example)? The phenol might interfere - might have to protect it - but you would get the 1-2-3 trisubstitution guaranteed.
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ITS A PUBLISHED PROCEDURE IT SHOULD WORK