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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: darkwizard267787 on October 28, 2022, 03:45:02 AM

Title: Why in the equation E=v/d E units are coulomb
Post by: darkwizard267787 on October 28, 2022, 03:45:02 AM

Hi,
I don't understand how volt/m=C.
because C is A*s
and v is J/C

I'm probably just doing it wrong, can someone explain me?

Title: Re: Why in the equation E=v/d E units are coulomb
Post by: Hunter2 on October 28, 2022, 04:49:15 AM

In which context is this all.v is it speed? Or what. V is volume.
What is m?  Mass?

J/C = U => J = Ws = VAs and C = As => VAs/As = V voltage.

Title: Re: Why in the equation E=v/d E units are coulomb
Post by: Borek on October 28, 2022, 05:50:52 AM

Quote from: darkwizard267787 on October 28, 2022, 03:45:02 AM

I don't understand how volt/m=C

Assuming from the context you mean V - volt (electric potential), m - meter (distance unit), C - coulomb (charge unit) - it is not, so whole discussion is a moot.

[tex]V = \frac {potential~~energy}{charge} = \frac J C = \frac {kg\times m^2}{C\times s^2} = \frac {kg\times m^2}{A\times s^3}[/tex]

V/m is an electric field unit.

Integrating the electric flux over a closed surface will yield electric charge inside the surface (Gauss law), so these are all closely related units and and ideas, but they don't produce the relationship you stated.

Title: Re: Why in the equation E=v/d E units are coulomb
Post by: mjc123 on October 28, 2022, 03:06:53 PM

Are you confusing E (electric field strength, in V/m) with e (elementary charge, in C)?