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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: streakz on October 26, 2004, 02:00:26 AM

Title: Nickel
Post by: streakz on October 26, 2004, 02:00:26 AM

A 10.00ml sample of an unknown aqueous nickel(II) solution was treated and found to produce 0.0532 g Ni(DMG)2 precipitate. Calculate the percent Nikckel in the ore sample.

i went from 0.0532/58.7 and got 9.00x10-4 .. im pretty sure im not on the rite track


Answer 0.108% nickel

Title: Re:Nickel
Post by: AWK on October 26, 2004, 03:35:05 AM

MM of (DMG)₂Ni is 288.7

Title: Re:Nickel
Post by: streakz on October 28, 2004, 10:30:15 AM

i got it now...
0.0532g g of Ni(DMG)2 x 1 mol / 288.7 MM = 1.84 x 10-4 mols
1.84 x 10-4 mol  x 58.7g Ni / mol = 0.0108g Ni
0.0108g x mL / 10.00g = 0.000108g x 100 = 0.108%

Title: Re:Nickel
Post by: AWK on October 29, 2004, 03:39:39 AM

OK