Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: 777888 on October 27, 2004, 04:25:32 PM
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I have some questions! Hope someone can help me :) Thank you
1)"An aqueous chlorine solution is added to a phosphorous acid solution"
Would the species initally present be: Cl2, H2O, H+, H3PO3 ?
INSTEAD OF: Cl2, H2O, H+, PO3(3-) ?
Becuase I can't find PO3(3-) in the redox table.
2)Question: Gold is added to an hydrochloric acid solution. Predict the redox reaction and determine if it's spontaneous.
Steps:
Species initally present: Au H+ Cl- H2O
By choosing the strongest reducing/oxidizing agents, and add the half-reactions together, I got the equation:
4H(+) +2H2O->2H2+O2+4H(+)
2H2O->2H2+O2 Subtract 4H(+) from both sides.
Problem: Would this be spontaneous?? How can I know this by the equation? (There's only 1 reactant in the net equation so I don't know how to determine which is oxidizing agent and which is reducing agent...)
3)Would the Cu-Fe cell's(Cu and Fe as electrodes, CuCl2, FeSO4 as electrolytes, and the salt bridge contains KNO3) cell potential be 0.34-(-0.44)=0.78 V?
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Phospohric acid is HPO4(3-) not HPO3(3-).
To determine if it is spontaneous calculate the Delta G for the RXn and if it in Negative it is spontaneous.
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Chlorine will oxidise phosporous acid to phosphoric acid.
H3PO3 is a diprotic acid and PO3(3-) does not exist.
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H3PO3 is dibasic in virtue of its structure:
H
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O=P(O-H)2
Only the hydrogen attached to the oxygen atoms are capable being released into solution as H+
For your gold question, just work out Ecell. It should be negative, ie. the reaction isn't spontaneous, because gold is less reactive than copper with bronsted acid.