Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: unkwown on November 23, 2006, 05:05:31 PM
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Hi i have an equation
CaCO3 + 2HCl -> CaCl2 + CO2 + H2O
how would this look ionically???? I dont know which ones are the spectator ions. I looked in textbox and on internet but i cant quite get it. I came up with
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-) + H2O
i think that is wrong
thanks for help
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How soluble is calcium chloride? ;)
http://en.wikipedia.org/wiki/Spectator_ion
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im still not sure. ive got my equation to
O3(2-) + 2H(+)Cl(-) -> Cl2 + O2 + H2O
but this cant be right
Can you give me the equation and tell me how you did it
thanks
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First of all, have you understood which are the spectator ions?
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-)
This is correct. For what concerns the rest, remeber that H2CO3-> H2O + CO2.
I can't give you the answer because of the rules of the website: we help people this way here.
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i know what a spectator ion is and i understand http://www.wpbschoolhouse.btinternet.co.uk/page01/ElCpdMix/EleCmdMix.htm#higher
EDIT: but can somebody please take me through this equation. I cant work it out
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H2CO3-> H2O + CO2.
hmm
i can understand the 3 oxygens are split and the 1 combines with 2 hydrogens to make water, but how would the equation look
thanks
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is this the ionic equation:
O3(2-) + 2H(+) -> CO2 + H2O
???
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nope wait...
i think its
C(4+)O3(2-) + 2H(+) -> CO2 + H2O
both have a charge of 0
can someone confirm that my ionic equation is right
Thankyou
;D
EDIT: or is it
2H(+) - > H2O
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1. CaCO3 is insoluble (well, it is weakly soluble, but you may assume it is insoluble) - thus it goes as CaCO3 into the equation.
2. Your original equation contains only two substances that will be completely dissociated and should be written as ions - which two?
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calcuim and chlorine? Am i right? So my equation: C(4+)O3(2-) + 2H(+) -> CO2 + H2O is right or wrong?
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calcuim and chlorine? Am i right? So my equation: C(4+)O3(2-) + 2H(+) -> CO2 + H2O is right or wrong?
Equation is wrong.
Calcium and chlorine are elements, I have asked about substances (compounds) that dissociate.
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im lost. Can't you just give me the equation and take me through how you got it?
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CaCO3 goes into the equation as solid.
HCl is strong acid, dissociated 100% - what ions are created?
CaCl2 is a soluble salt - dissociated as well - what ions are created?
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Your original equation contains only two substances that will be completely dissociated and should be written as ions - which two?
The only substance i can find that is disacciated is CalcuimChloride. Is CarboneDioxide the other one?? Meaning my final equation is
2H(+) - > H2O
what am i doing wrong?
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CaCO3 goes into the equation as solid.
HCl is strong acid, dissociated 100% % - what ions are created
CaCl2 is a soluble salt - dissociated as well - what ions are created?
Hydrogen Ions react with the O(-) ions. Hydrogen ions make somthing acidic and O(-) ions make somthing a base. Are the ions created H(+) Cl(-) and Ca(2+) Cl(-)???
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No such thing as O- ions, you probably mean OH-. They are of no use here.
Are the ions created H(+) Cl(-) and Ca(2+) Cl(-)???
Yes. Finally we are moving ahead ;)
Now, ALL you have to do is to rewrite the original reaction (the one you have posted in your very first letter) putting these dissociated substances into it. Don't touch CaCO3, nor CO2 nor water.
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Can i just clarify is calcuim an ion? Calcuim is an element right wanting to lose 2 electrons to make outershell complete. Why do i write it as an ion, with the 2+ above it? It hasn't lost any electrons.
I can only get my equation down to
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-)
From my orginal question, which ions are the spectator ions?
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Don't touch CaCO3, nor CO2 nor water.
What's left among the products? ;)
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Can i just clarify is calcuim an ion? Calcuim is an element right wanting to lose 2 electrons to make outershell complete. Why do i write it as an ion, with the 2+ above it? It hasn't lost any electrons.
I can only get my equation down to
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-)
From my orginal question, which ions are the spectator ions?
Calcium in calcium carbonate is already in ionic form - but, as the salt is insoluble, you don't write it as ion.
In the final equation please don't use form Ca(2+)Cl2(-) as it is probably source of the part of the confusion. What you have is Ca2+ + 2 Cl-.
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Don't touch CaCO3, nor CO2 nor water.
What's left among the products? ;)
I am afraid you are not helping, but just adding to the unkwown confusion. His original equation listed all correct products, not necesarilly in the ionic form. But H2O and CO2 were OK.
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can we start again :-\
I have the equation:
CaCO3 + 2HCl --> CaCl2 + H20
Calcuim Carbonate + Hydrochloric Acid --> Calcuim Chloride + Water
which goes to:
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-) + H2O
is this correct so far?
Can i asK:
Calcuim is an element right wanting to lose 2 electrons to make outershell complete. Why do i write it as an ion, with the 2+ above it? It hasn't lost any electrons yet??
Thankyou
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Calcuim is an element right wanting to lose 2 electrons to make outershell complete. Why do i write it as an ion, with the 2+ above it? It hasn't lost any electrons yet??
Calcium tends to lose 2 electrons, yeah, but in the carbonate it has already lost it's valence electrons, so it is impossible for the charged ion to lose other 2 electrons!
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CaCO3 + 2HCl --> CaCl2 + H20
Calcuim Carbonate + Hydrochloric Acid --> Calcuim Chloride + Water
which goes to:
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-) + H2O
it isn't correct. Only strongly dissociation substance may be change to ionic. so you can't write CaCO3 to Ca2+CO32-.And that reaction can be write:
CaCO3 + 2H+ ---> Ca2+ + CO2 + H2O
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When you talk about a dissociation substance, do you mean a compound that has been bonded ionoically? Ive never heard of the term dissociation (maybe it's a amercianism?)
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http://en.wikipedia.org/wiki/Dissociation_%28chemistry%29
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cheerz. Another question:
a isotope is define: Nuclei containing the same number of protons but different numbers of neutrons. Most elements can exist in several isotopic forms. A common example of an isotope is deuterium, which differs from normal hydrogen by the presence of an extra neutron in the nucleus.
but in the perodic table loads of element have a different number of neutrons to protons:
Al has 14 protons and 13 neutrons, does this make it an isotope.
isn't hydrogen a isotope
But i've search and hydrogen isn't a isotope, the first one is deuterium
are about half the elements isotopes then?
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Don't post different question in an old thread, start new one whe the question is new.
Every atom is an isotope.
Hydrogen has three isotopes - hydrogen (sometimes called protium), deuterium and tritium. In fact there are much more hydrogen isotopes, but these three are most important.
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a isotope is define: Nuclei containing the same number of protons but different numbers of neutrons.
..
but in the perodic table loads of element have a different number of neutrons to protons:
You have misunderstood the definition.
The tree most important isotopes of H, as Borek has already said, are protium, deuterium and tritium
Protium ("normal" hydrogen): 1 proton, 0 neutrons
Deuterium: 1 proton, 1 neutron
Tritium: 1 proton, 2 neutrons.
Now, all three have the same number of protons in the nucleus (1) but the number of neutrons vary, so protium, deuterium and tritium are said to be isotopes of hydrogen.
In the same way, 35Cl and 37Cl (the superscript number is the atomic mass) are isotopes of Cl. Both have 17 protons, but the number of neutrons differ. These are the main isotopes of Cl, and exist in a 3:1 ratio of 35Cl to 37Cl (approximately), which is why the atomic mass of Cl is quoted on periodic tables as about 35.5.