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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: g00ber on December 01, 2004, 09:05:55 PM

Title: Homework Help: pH dilution
Post by: g00ber on December 01, 2004, 09:05:55 PM

What is the pH of the solution formed by diluting 25.0 mL of 0.40 M NaOH to a final volume of 2.00 L?

Title: Re:Homework Help: pH dilution
Post by: Mitch on December 01, 2004, 11:19:50 PM

You have to attempt the problem.

Title: Re:Homework Help: pH dilution
Post by: AWK on December 02, 2004, 01:20:27 AM

Calculate a new concentration and take into account NaOH is a strong base.

Title: Re:Homework Help: pH dilution
Post by: bindy on December 04, 2004, 02:48:34 AM

if 0.4M NaOH means the quantity of matter,then C(hydroxyl)=0.4/2=0.2Mol/L
Ph=14-POH=14+lg0.2=13.3010

Title: Re:Homework Help: pH dilution
Post by: Donaldson Tan on December 04, 2004, 08:17:25 PM

Quote from: g00ber on December 01, 2004, 09:05:55 PM

What is the pH of the solution formed by diluting 25.0 mL of 0.40 M NaOH to a final volume of 2.00 L?

0.4M NaOH is diluted from 0.025L to 2L.

Concentration of diluted NaOH = 0.4 / (2/0.025) = 5 x 10^-3

this should help you out.