Chemical Forums
Specialty Chemistry Forums => Other Sciences Question Forum => Topic started by: Sis290025 on March 09, 2007, 11:29:51 PM
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A pair of point charges, q = 7.60 microC and q' = -4.50 microC, are moving in a reference frame, as shown in the figure, with speeds 9.00×10^4 m/s and v' = 6.40×10^4 m/s.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fi131.photobucket.com%2Falbums%2Fp289%2FSoaringCrane%2Fyf_Figure_28_30.jpg&hash=c765571583d983b28661c7d4767294abfdff81ff)
a. When the point charges are at the locations shown in the figure, what magnetic force does q' exert on q?
b. What is its direction?
I came across a formula for the magnetic force F_a on b:
F_ab = q_b*v_b[(mu_0/(4*pi)]*[(q_a*v_a*u_ab)/r^2]
where u_ab = unit vector directed from q_a to q_b
Shortened F_ab = q_b*v_b*B_a??
I really don’t know if I used the formula properly, so:
Magnitude B_q’ = [mu_0/(4*pi)]*[(q_a*v_b*u_ab)/r^2 = [mu_0/(4*pi)]*[(q_a*v_b*r_ab)/r^3
= (1.0*10^-7)*(32000 m^2/s)*(4.50*10^-6 C)/[0.500m]^3
= 819.2 T ??
Magnitude F_q’ on q = q*v_q*B_q’ = ((7.60*10^-6 C)*(9.00*10^4 m/s)*819.2 T) = 560.33 N ??
Will the force’s direction be in the positive(+) y-direction?
Thank you.