Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: indianprince on December 11, 2004, 06:49:33 AM
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My Chem Sir gave me a real toughie of a problem....
This is the question:
Balance the reaction in basic medium..
CrI3 + H2O2 + OH- ------> (CrO4)2- + (IO4)- + H20
I got these things clear:
Cromium is oxidised from +3 oxidation state to +6 oxidation state
Iodine is also oxidised from -1 to +7 oxidation state
Hydrogen Peroxide is reduced to Water
I dont know how to proceed as since there are two oxidation half reactions and one reduction reaction.. ??? :'(
Any help on this prob will be greatly appreciated. :)
and how to solve such similar probs when more than a single oxidation or red reaction is taking place?
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Nothing prevents you from including both oxidations into one half reaction:
CrI3 + OH- -> (CrO4)2- + (IO4)- + H20 (unbalanced)
H2O2 --> OH- unbalanced