Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Abilio on May 23, 2007, 11:30:19 AM
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Hi,
I'm interested in the bismuth - bromide complexes. If anyone has information about it please let me know.
I have a software called MEDUSA that makes diagrams of complexes and ions in solution and it does not show the bromide complexes of bismuth but i know that such complexes really exist.
Thanks for helping me.
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Bi3+/Br-
ß1 = 3.06
ß2 = 5.6
ß3 = 7.4
ß4 = 8.6
ß5 = 9.2
ß6 = 8.7
ß6 = [BiBr63-]/([Bi3+][Br-]6)
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Hi Borek, thanks for the post but i don't know the meaning of beta ???... Can you help me?
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I have explained what ß6 is at the very bottom of my post. All other are analogous.
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Now i understand. Thanks!!!