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Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Abilio on May 23, 2007, 11:30:19 AM

Title: Bismuth - Bromide complexes
Post by: Abilio on May 23, 2007, 11:30:19 AM
Hi,

I'm interested in the bismuth - bromide complexes. If anyone has information about it please let me know.

I have a software called MEDUSA that makes diagrams of complexes and ions in solution and it does not show the bromide complexes of bismuth but i know that such complexes really exist.

Thanks for helping me.
Title: Re: Bismuth - Bromide complexes
Post by: Borek on May 24, 2007, 03:37:00 AM
Bi3+/Br-

ß1 = 3.06
ß2 = 5.6
ß3 = 7.4
ß4 = 8.6
ß5 = 9.2
ß6 = 8.7

ß6 = [BiBr63-]/([Bi3+][Br-]6)
Title: Re: Bismuth - Bromide complexes
Post by: Abilio on June 28, 2007, 11:46:22 PM
Hi Borek, thanks for the post but i don't know the meaning of beta  ???... Can you help me?
Title: Re: Bismuth - Bromide complexes
Post by: Borek on June 29, 2007, 02:56:26 AM
I have explained what ß6 is at the very bottom of my post. All other are analogous.
Title: Re: Bismuth - Bromide complexes
Post by: Abilio on June 29, 2007, 05:34:50 PM
Now i understand. Thanks!!!