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Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: Imrahil on January 15, 2005, 02:52:45 PM

Title: Calorimeter Problem
Post by: Imrahil on January 15, 2005, 02:52:45 PM

I have this problem that I just cant do, I dont understand how to do it! Please help me find the answer!!! ok here it is.

When ice melts at 0 degrees celsius to form liquid water, it absorbs 334J/gram. The specific heat of water is 4.184 J/gc. Suppose the heat needed to melt a 35.0g ice cube is absorbed from water (210g) in a calorimeter at 21 degrees celsius. What is the final temp of water?

Apparently the answer is 6.6 degrees celsius.

Thanks

Title: Re:Calorimeter Problem
Post by: Demotivator on January 15, 2005, 10:17:55 PM

35g(334j/g) = 210g(4.184j/gC)(21-T)