Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: nicholasbellono on September 28, 2007, 02:26:20 PM
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Balance equations:
Aqueous solutions of Cu(NO3)2, Na2CO3 are mixed and produce a blue precipitate of CuCO3.
I wrote Cu(NO3)2 + Na2CO3 --> 2CuCO3
What does the blue mean and how should i express that?
or am I right with what I have?
Another balancing equation has to deal with neutralization:
aqeous solutions of NaOH and H2SO4 are mixed. The neutralization of water is formed with the evolution of heat.
How do I go about balacing this one?
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Cu(NO3)2 + Na2CO3 --> 2CuCO3
What happened to Na+ and NO3-?
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i don't know. I guess that is what I'm asking. where does it go
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Let's see... sodium and nitrate... sodium nitrate?
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I know what sodium and nitrate make. But what does the blue mean?
does it have an significance to my equation.
Here is what I have down right now:
Cu(NO3)2+ Na2CO3 ---> CuCO3 + Na2(NO3)2
Then for NaOH and H2SO4:
NaOH + H2SO4 ---> Na2SO4 + H20
Thanks for the help-
Am i on the right track?
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I know what sodium and nitrate make. But what does the blue mean?
Precipate was blue, you don't put it in the reaction equation, you should write in down in the observations done during experiment.
Cu(NO3)2+ Na2CO3 ---> CuCO3 + Na2(NO3)2
Better, although sodium nitrate formula looks different.
NaOH + H2SO4 ---> Na2SO4 + H20
That's correct skeletal equation. Don't forget to balance it :)
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thanks!
here is what i came up with now:
2NaOH + H2SO4 --> Na2SO4 + 2H20
and
Cu(NO3) + Na2CO3 --> CuCO3 + 2NaNO3
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Seems OK :)
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Borek- thanks for the help. I really appreciate it.