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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: lardhaterplz on October 01, 2007, 09:38:57 PM

Title: I have a question about a limiting reactant problem.
Post by: lardhaterplz on October 01, 2007, 09:38:57 PM

Strontium chloride, SrCl2, reacts with sodium phosphate, Na3PO4 to form a precipitate according to the following reaction:

3 SrCl2 (aq)  +  2 Na3PO4 (aq)  ->  Sr3(PO4)2 (s)  +  6 NaCl(aq)
   
If 50.0 mL of 0.10 M SrCl2 is mixed with 50.0 mL or 0.10 M Na3PO4, how many grams of precipitate are formed?

ok, So I've set up the equation for the first part as:

?grams of Sr3(PO4)2 = 50 mL Na3PO4 x (1L/1000mL)(.10M Na3PO4/1 L Na3PO4)(163.94g Na3PO4/1 mol Na3PO4)(1 mol SrPO4/2 mol Na3PO4) = .40985 grams of SrPO4

Is this first part correct? I am studying for an exam tomorrow. Thank you so much!

Title: Re: I have a question about a limiting reactant problem.
Post by: agrobert on October 01, 2007, 10:09:10 PM

How do you know if sodium phosphate is limiting?  If strontium chloride is limiting your answer is wrong.  Show the determination of the limiting reagent.