Chemical Forums
Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: University_Of_Toronto on November 03, 2007, 12:55:16 AM
-
Buffer capacity (Acid/HCl) = -1/slope * [HCl]/ Volbuffer
I ended up with mol/L...just wondering if it is correct
-
TBH I have no idea what you wrote - what does "Acid/HCl" means? Is that you buffer definition capacity? If so, isn't HCl an acid? Doesn't it cancel? How can you calculate buffer capacity not taking pH change into account? Something is wrong.
http://www.chembuddy.com/?left=pH-calculation&right=pH-buffer-capacity
-
Well you focus on the what (HCl/NaOH) means rather than focusing on the question...the question remained unanswered but I will explain to you what buffer capacity(HCl/NaOH) means
If you add HCl/NaOH to a buffer then the
Experimental buffer capacity can be calculated from the slopes of the graphs of pH vs NaOH added or pH vs HCl added
Experimental Buffer capacity= 1/mHCl * ConHCl / Vbuffer
Now you are refering to theoretical Buffer capacity which is
B(beta) =[(H + Kw/H + Ka CH/(Ka +H)2] ln (10)
I dont know but it seems there are too many police here rather than people who are willing to atleast provide some assistance
I already got what I wanted from the link you provided but thanx anyways
-
Well you focus on the what (HCl/NaOH) means rather than focusing on the question...the question remained unanswered but I will explain to you what buffer capacity(HCl/NaOH) means
No, I am focusing on what you mean - it is impossible to answer the question without understanding it :) And your post was - at least for me - far from being clear.
Experimental buffer capacity can be calculated from the slopes of the graphs of pH vs NaOH added or pH vs HCl added
Experimental Buffer capacity= 1/mHCl * ConHCl / Vbuffer
Assuming you started with mentioned plot, slope = ΔpH/ΔV, so buffer capacity is
Experimental Buffer capacity= ΔV/ΔpH * ConHCl / Vbuffer
Now, when it comes to units volume cancels out and you are left with concentration/pH - if we assume pH is unitless, what is left is concentration - so you were OK from the begining. Not knowing what you mean by "slope" there was no way of checking.
-
Thank you Borek..you deh man ;D