Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: yosh on January 10, 2008, 06:48:30 PM
-
How do you simplify (e^(e^(25)))
-
You punch it into the calculator ;)
(it is a constant)
-
In other words - you don't. As long as 25 is an integer number ee25 is an exact value, replacing it with anything else will be approximate only.
-
ee25 =e25e
There is no further simplification possible. I hope that helped you anyway.
-
ee25 =e25e
There is no further simplification possible.
No, I don't think even this is correct. For this to be true, 25e and e25 would have to be equivalent, they're not.
25e1 ~ 68.
-
ee25 =e25e
There is no further simplification possible. I hope that helped you anyway.
You are wrong twice :) First - it is not correct. Second - assuming it is correct, further simplifaction is possible and e25e is simply 25e2 ;)
-
Next on the chopping board: Borek ;)
Second - assuming it is correct, further simplifaction is possible and e25e is simply 25e2 ;)
25e2 is only about 185, much smaller than e25e.
You are likely thinking of a log rule :)
-
Next on the chopping board: Borek ;)
Next one answering before understanding: Brett.
Second - assuming it is correct, further simplifaction is possible and e25e is simply 25e2 ;)
25e2 is only about 185, much smaller than e25e.
You are likely thinking of a log rule :)
You have missed the point. Reread my posts.
-
Oops, I understand now, sorry I guess I was a bit hasty :-[
But you have forgotten that further simplification is possible as 25e2=50e ;)
-
But you have forgotten that further simplification is possible as 25e2=50e ;)
Good point, missed that one :)