Chemical Forums

Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: libra78wolf on February 24, 2005, 08:20:34 PM

Title: Equation Writing
Post by: libra78wolf on February 24, 2005, 08:20:34 PM
I did a  workshop and am having a few problems understanding three of the questions.

When Benzene, is burned in excess of oxygen

my teacher gave us the answers
2C6H6 + 150--> 6H2O+CO2

A piece of rubidium is dropped in water., a violent reaction occurs
2RB+H2O-->2RbOH + H2
why can't you just write RbH2O: referring to reactant side?

A solution of ammonia is mixed with a solution of sulfric acid

2NH3+H2SO4-->(NH4)2SO4

Why does it change to ammonium on the reactant side with a subscript of 2?
Title: Re:Equation Writing
Post by: Dante on February 24, 2005, 11:11:59 PM
Maybe i can help in this situation (Rubidium one)

I know one thing about water, they can't be other element be one with them (RbH2O) so it is not a weird thing when Rubidium Hydroxide occurs. Hope Helps
Title: Re:Equation Writing
Post by: AWK on February 25, 2005, 01:55:13 AM
Quote
2C6H6 + 150--> 6H2O+CO2

Should be
2C6H6 + 1502 --> 6H2O+12CO2

Quote
why can't you just write RbH2O: referring to reactant side?

A gaseous H2 is evolved, hence we should write down two compounds

Quote
Why does it change to ammonium on the reactant side with a subscript of 2

Chemists use a specific kind of "chemical algebra" to write down empirical formulas and reactions.