Chemical Forums
Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: 21385 on February 06, 2008, 06:31:50 PM

The question is in two parts.
a) Consider the n=3 state of the Be(2+) ion. What is the radius of the electron orbit of this ion, relative to the nucleus? a) 1.17Å (b) 1.18Å (c) 1.19Å (d) 1.20Å (e) 1.21Å
b) Consider the n=2 state of the Be(2+) ion. What is the velocity of the electron orbiting the nucleus, relative to the nucleus?
(a) 4.38 x 10^4 m/s (b) 4.38 x 10^5 m/s (c) 4.38 x 10^6 m/s
(d) 4.38 x 10^7 m/s (e) cannot be determined from given data
I basically have no idea what to do with these problems, it would be really great if someone could tell me the method to solve this problem. Thanks

Since Be^{2+} has only one electron, you can treat it as a hydrogen atom with Z = 3.

Doesn't Be(2+) have the same number of electrons as a helium atom, not a hydrogen atom?
also, can someone tell me the formulas? because I don't seem to learned this formula at all
Thanks a lot

Ah, my bad. I don't know if there are simple equations you can use for a heliumlike atom. The problem would be much simpler for Be_{3+} since you could use the equations for the hydrogen atom.