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Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: xXAznGirlXx on February 19, 2008, 02:19:38 PM

Title: Redox Titration -Determine the % of Iron II and Iron III
Post by: xXAznGirlXx on February 19, 2008, 02:19:38 PM

determine the % of iron II and iron III in a mixture containing both, where i am given 200cm3 of a solution containing 1.3g of iron ions(Fe 2+ Fe 3+) using potassium magnanete.
I wrote down the equation already, and method, but i don't know how to work out the % from it :/
Can you please help or any ideas how to start?

Title: Re: Redox Titration -Determine the % of Iron II and Iron III
Post by: JGK on February 19, 2008, 02:45:01 PM

Titrating an aliquot of your sample with the potassium manganate will allow you to determine the concentration of Iron (II) in the sample, if you know that and the total iron in the sample the rest is easy.  8)

Title: Re: Redox Titration -Determine the % of Iron II and Iron III
Post by: xXAznGirlXx on February 19, 2008, 06:05:45 PM

oh ok thanks alot!!
So once I found out the concentration , do i find the % from that?

Title: Re: Redox Titration -Determine the % of Iron II and Iron III
Post by: LQ43 on February 19, 2008, 09:41:30 PM

If you have concentration of the Fe²⁺ion and know the volume of your aliquot, you can get mol of Fe²⁺, then calculate gms Fe²⁺.

mass Fe²⁺/volume aliquot =  total mass of Fe²⁺/200cm³ sample


total mass Fe²⁺/ 1.3g  = %

Title: Re: Redox Titration -Determine the % of Iron II and Iron III
Post by: xXAznGirlXx on February 20, 2008, 09:02:28 AM

ohh yeah thanks :) sorry but what is gms?

Title: Re: Redox Titration -Determine the % of Iron II and Iron III
Post by: JGK on February 20, 2008, 09:50:23 AM

gms = grams = g  :-\