Chemical Forums
Specialty Chemistry Forums => Biochemistry and Chemical Biology Forum => Topic started by: Seks on March 16, 2008, 02:07:52 PM
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300 ml of 0.2 M of one of the 20 standard amino acids.
Titrate with 1.0M NaOH.
I am given a titration curve.
How do I determine which amino acid got titrated?
.3*0.2 = .06 mol of amino acid
Assuming using .3L of NaOH,
.3*1 = .3 mol of NaOH
I'm not sure where to go from here? ???
For some reason I always have trouble with titration problems :(
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It's a shape of the curve that holds necessary information.
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Here are the pKa's for the 20 amino acids and their acidic groups.
http://www.bmrb.wisc.edu/referenc/aapka.html
Also notice and memorize the general pKa's for the Carboxylic group and the amine group.
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On the curve,
0.5 OH- added, it's at pH 2
1.5 OH- added, it's at pH 8
2.5 OH- added, it's at pH 10ish
(pH for 1.0, 2.0, 3.0 OH- added are indicated but I dont' think those values are relevant??)
I use that pH = pKa + log [A-]/[HA] equation, where A- = .3 and HA = .06.
But for pH 2 and 8, I get pKa 1.3 and 7.3 respectively. And those values don't jive with any pKa values on my table of amino acids.
I must be missing something???? or a step somewhere...
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Exactly between equivalence points of a titration curve, [A-] = [HA]. What does this tell you about the pKa values for the various functional groups on the amino acid?
[edit: thanks for the correction Borek]
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At the equivalence point of a titration curve (where pH changes sharply with added OH), [A-] = [HA].
Sounds like one of these "before coffee" answers ;)
What Ygg is trying to point out is that there are points on the curve where pH=pKa without any further corrections.
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Well, when 0.5 OH- is added, pKa = pH, so which means that's pKa 2.
1.5 OH-, pKa = 8
so on
But using 1 mol/L of OH- for 0.3L of 0.2 mol/L amino acid, how will those amounts/quantities affect what I'm trying to find? :(
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But using 1 mol/L of OH- for 0.3L of 0.2 mol/L amino acid, how will those amounts/quantities affect what I'm trying to find? :(
Assuming 0.5 OH- means just molar ratio of base added to your aminoacid, concentrations don't matter (much, they do a little, but the effect can be neglected). It is their ratio that counts - and ratio is what you use as input.