Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Marcus Soutlo on March 30, 2008, 01:51:10 PM
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Calculate the solubility of silver chloride in a 0.1 mol/L solution of sodium chloride at 25°C.?
At SATP, Ksp AgCl(s) = 1.8 x 10^-10
What did I do wrong?
AgCl <----> Ag+ + Cl-
[Ag+] = x
[Cl-] = x + 0.1
Ksp = [Ag+] [Cl-]
1.8 x 10^-10 = (x) ( x + 0.1)
x = molar solubility = 1.8 x 10^-9 M