Chemical Forums
Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: Robertsays on April 04, 2008, 09:45:55 AM
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Cr2O72- + (NH4)2SO4.Fe2SO4.6H2O -->
Can anyone help me out here?
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Please read forum rules (http://www.chemicalforums.com/index.php?page=forumrules).
Mohr's salt is dissociated in this reaction. Split it into ions, than think what is reacting with what - you have an oxidizer and a reducing agent.
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sorry,
Cr2O72- + 14H+ + 6e- ---> 2Cr3+ + 7H2O (reduction)
Fe2+ ---> Fe3+ + e- (oxidation)
so,
Cr2O72- + 6Fe2+ + 14H+ --> 2Cr3+ + 6Fe3+ + 7H2O
but do the ammonium and sulfate ions react with anything? seems too simple.
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They are just spectators. And your equation is correct :)