Chemical Forums

Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: selway on April 01, 2005, 04:14:44 PM

Title: pH 12 diluted with pH 8
Post by: selway on April 01, 2005, 04:14:44 PM

Hello, I have a complicated pH question.  I have a 8 inch pipe that discharges 20,000 gallons/day and measurements of the pipe pH are 12.  If the volume was increased to 40,000 gallons/day with water with a pH of 8, what would the final pH be?

I am so confused.  I tried calculating moles of H+, but my volume is a rate, not an actual volume, so how do I change that to mol/liter?

AND, what if I just know the pH but not the chemical that is providing it?  

Title: Re:pH 12 diluted with pH 8
Post by: Borek on April 01, 2005, 05:30:08 PM

Forget about rates. Imagine you have collected all water in the poll and make your calculations on known volumes.

Title: Re:pH 12 diluted with pH 8
Post by: AWK on April 04, 2005, 02:42:28 AM

As a first aproximation, you can treat the problem, as dilution of water with pH=12  (twice). Forget about water with pH=8