Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: upsidedown on May 29, 2008, 04:38:23 PM
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I know when cracking usually an alkane and an alkene is produced, but why when cracking hexane the equation
C6H14 → C3H6 + C3H8
and not C6H14 → C4H8 + C2H6
because both are an alkane and an alkene.
Thanks for any help
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I know when cracking usually an alkane and an alkene is produced,
Agreed
but why when cracking hexane the equation
C6H14 → C3H6 + C3H8
and not C6H14 → C4H8 + C2+H6
because both are an alkane and an alkene.
Is "C2" an alkane or alkene ?
Is "H6" an alkane or alkene ?
But separately, I have read that cracking produces a "variety" of hydrocarbon (emphasis intended) products . So going back to your first equation
C6H14 → C3H6 + C3H8
I'm not sure that C3H6 + C3H8 will be the only products - which is where you came in.
Now ... going back to what you wrote I guess you made a slight slip and meant
C6H14 → C4H8 + C2H6
which balances OK.
However, it might be the case that the energy of the various paths favour the production of certain products rather than others, or that there might be "rules" that guide where the splitting takes places - but I haven't come across them.
I too will be interested to find out if there is a "definitive" answer to this.
Clive
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Sorry the C2+H6 is a typing mistake, I have corrected it now.