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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Herst on June 16, 2008, 09:32:12 PM

Title: Writing a ReDox Reaction
Post by: Herst on June 16, 2008, 09:32:12 PM

"The reaction between aqueous solutions of Cu(NO3)2 and KI  form CuI and I2. The CuI precipitates from the reaction as a solid, and the other products (KNO3 and I2) remain in aqueous solution.

Write a balanced molecular equation for the overall reaction, using the smallest whole number coefficients, including the states of matter for each reactant and product."

The only answer I can think of is

Cu(aq) + I(aq) -> CuI(aq)  , which I found by removing the spectator ions and keeping the molecules         which are necessary for precipitation.

Can someone help me understand how to do this please?

Title: Re: Writing a ReDox Reaction
Post by: AWK on June 17, 2008, 01:09:19 AM

Balance it
Cu(NO3)2(aq) + KI(aq) = CuI(s) + KNO3(aq) + I2(s)

Title: Re: Writing a ReDox Reaction
Post by: Borek on June 17, 2008, 03:14:06 AM

Quote from: Herst on June 16, 2008, 09:32:12 PM

The only answer I can think of is

Cu(aq) + I(aq) -> CuI(aq)

First of all - I₂ should be a product, it is not in your reaction equation.

Second - you have omitted charges, you can't. Your must balance both atoms and charge.