Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Tootella on June 25, 2008, 03:57:19 PM
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Hello!
We did an oxidation experiment in lab today. As part of post-lab, we have to draw the structures of different cyclic alkenes that have been treated with a variety of compounds.
One of the questions asks: what will the product be if an alkene is treated with 1) O3 2) Zn, H2O
Everything I've read about O3 (ozonolysis) has the reaction take place in the presence of (CH3)2S (dimethylsulfide). I know that that does a cleavage and can give ketones and aldehydes as products. Will doing a reaction with O3 in the presence of Zn, H2O do the same thing, or will the presence of these things give a fully oxidized product?
I'm sorry if this is not clear. Let me see if I can summarize it...
Will treating an alkene with
1) O3 2) (CH3)2S
or
1) O3 2)Zn, H2O
do the same thing? Will the second option give a fully oxidized product?
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hey.
ozone in either zinc and water or dimethyl sulfide will cut that carbon carbon double bond and turn it into a double bond oxygen.
They both give out the same products.
That's cool that they let you do that in the lab!
The only thing I can think of that will give you a fully oxidized product is to add Cr(6+) in H2SO4.
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Thank you sooo much!!! :-*
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hey.
ozone in either zinc and water or dimethyl sulfide will cut that carbon carbon double bond and turn it into a double bond oxygen.
They both give out the same products.
That's cool that they let you do that in the lab!
The only thing I can think of that will give you a fully oxidized product is to add Cr(6+) in H2SO4.
Ozone and an alkyne should give the carboxylic acid right?
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No. Ozone is a mild oxidizing agent. It will not reduce your compound all of the way to a carboxylic acid.
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macman got it right. :)