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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: dmk007 on July 07, 2008, 08:21:08 AM

Title: % of antimony in an alloy??
Post by: dmk007 on July 07, 2008, 08:21:08 AM

Hey i'd appreciate it if someone could help me with this... i think the answer is 7.214 %
Balance the following equation
KMnO4 + Sb(SO4)3 + H2SO4 - MnSO4 + Sb2(SO4)5 + K2SO4 + H20

In the determination of the % of antimony (Sb) in an alloy. 1.67g of the alloy were dissolved in excess sulphuric acid. When the solution was cooled and diluted, it was titrated with standard potassium permanganate solution, containing 2.95g of KMnO4 per dm3. The volume of potassium permanganate required was 21.2 cm3. Calculate the percentage of antimony in the alloy and calulate the number of grams of sulphuric acid used in this reaction..

Title: Re: % of antimony in an alloy??
Post by: Astrokel on July 07, 2008, 08:54:40 AM

Hey!

Where did you get the equation? It's not right, that's why you cannot balance it.

Title: Re: % of antimony in an alloy??
Post by: dmk007 on July 07, 2008, 08:58:00 AM

sorry about that it should be Sb2(SO4)3 not Sb(SO4)3

Title: Re: % of antimony in an alloy??
Post by: Astrokel on July 07, 2008, 09:34:03 AM

Balance Sb first then K, Mn, SO4, and lastly balance the O and H using H2O

Title: Re: % of antimony in an alloy??
Post by: dmk007 on July 07, 2008, 09:38:38 AM

Thanks what about the rest of the question?

Title: Re: % of antimony in an alloy??
Post by: Astrokel on July 07, 2008, 10:06:42 AM

The rest is all simple stoichiometry after you know the mole ratio of KMnO4: Sb2(SO4)