Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: 113zami on August 15, 2008, 07:24:09 PM
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I know that when OH ions are added to a weak acid buffer they will combine with the weak acid and more H+ ions will be released into solution as a result, but how does that happen equation wise?? ie. if this is the weak acid buffer equation (before OH addition):
HA ---> H+ + A-
and this is the equation after you add the OH ions
HA + OH ---> A- + H2O
there are no H+ ions in the above equation, so where are these H+ ions that should be released into solution after the OH addition coming from??
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hey!
Weak acid buffer consist of a weak acid, HA and a salt of the acid's conjugate base, NaA.
HA(aq) <----> H+ + A-
NaA ----> Na+ + A-
Due to the dissociation of NaA, there will be large reservoir of A-, this shifts equilibrium of the acid dissociation to the left. So at equilibrium, there will be large reversoir of HA acid, A-(from the salt), little amount of H+, from what i heard the equilibrium to the left shifts up to 97%, so H+ is almost negligible, even if it does reacts with the OH-, it will form H2O, but probably only a small amount.