Chemical Forums
Specialty Chemistry Forums => Other Sciences Question Forum => Topic started by: Mitch on September 01, 2008, 09:02:46 PM
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Derive this formula.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B%5Cleft%28%5Cfrac%7B%5Cpartial+x%7D%7B%5Cpartial+y%7D%5Cright%29_%7Bz%7D+%3D+-+%5Cleft%28%5Cfrac%7B%5Cpartial+x%7D%7B%5Cpartial+z%7D%5Cright%29_%7By%7D%5Cleft%28%5Cfrac%7B%5Cpartial+z%7D%7B%5Cpartial+y%7D%5Cright%29_%7Bx%7D+%7D&hash=6876465a6b4b65a2e2c5fa03a6aad0e45bca98f0)
I was given this as a hint:
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7Bdz+%3D+%5Cleft%28%5Cfrac%7B%5Cpartial+z%7D%7B%5Cpartial+x%7D%5Cright%29_ydx+%2B+%5Cleft%28%5Cfrac%7B%5Cpartial+z%7D%7B%5Cpartial+y%7D%5Cright%29_xdy%7D&hash=4eeb02fa1c6c511df62084e2ceb8b172a0a180e3)
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Exact quote from a much more talented math friend than I "divide by dy, then move s#*$ around".
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Solve it how? I mean, you already have something equal to something else. Where are you trying to go with it?
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The problem just says "Derive this formula." This is from Chandler's Introduction to Modern Statistical Mechanics, problem 1.9
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Are you sure in that hint that the last partial derivative is not supposed to be (partial Z / partial Y) at constant X times dy?
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Yeah, you're right. Latex is still a bit confusing, still getting use to it.
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I PDF'd it. I am already pissed enough. I just wrote it out and planned on scanning it, but just found out my scanner is broke! I hate doing forumals on a computer, so hopefully I did not skip to much for you when typing it up.
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That is fantastic. Thanx! I've been working on it since Friday to no avail. I owe you a big one, let me know whenever you need it cashed in.
+10 karma, for going to all that trouble.
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Exact quote from a much more talented math friend than I "divide by dy, then move s#*$ around".
divide by 'dy' while keeping z constant . A simple rearrangement yields the relation.