Chemical Forums
General Forums => Comments for Staff and Comments from Staff => Topic started by: Mitch on September 06, 2008, 03:45:06 AM
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Examples follow:
If you want to display (https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+y+%3D+%5Cmathrm%7Bm%7Dx+%2B+%5Cmathrm%7Bb%7D+%7D&hash=f8a2f199512c8e94bb1e0c5b0d7ecba16efb4d4a)
Use the following code
## y = mx + b /##
Here is another one: (https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+%5Cmathrm%7Bd%7DE+%3D+%5Cleft%28%5Cmathrm%7Bd%7DQ%5Cright%29_%7B%5Cmathrm%7Brev%7D%7D%5C%2C+%2B%5C%2C+%5Cmathrm%7Bd%7DW+%7D&hash=879eb125987ae8e1c1dd9780ce479f8d3e14f03f)
Simply put this:
## dE = (dQ)_{rev} + dW /##
I hope this makes life easier for you guys. Feel free to practice in this thread.
Mitch
Here is a tutorial for using math with latex:
http://theoval.sys.uea.ac.uk/~nlct/latex/novices/displaymath.html
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(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+%5Cmathrm%7BC%7D_6%5Cmathrm%7BH%7D_%7B12%7D%5Cmathrm%7BO%7D_6%5C%2C+%2B%5C%2C+6%5Cmathrm%7BO%7D_2+%5C%2C%5Crightarrow%5C%2C+6%5Cmathrm%7BCO%7D_2%5C%2C+%2B%5C%2C+6%5Cmathrm%7BH%7D_2%5Cmathrm%7BO%7D+%7D&hash=57bba01a62610d0040d5453a70d85557d3b3428d)
## \mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\, +\, 6\mathrm{O}_2 \,\rightarrow\, 6\mathrm{CO}_2\, +\, 6\mathrm{H}_2\mathrm{O} /##
I'm really not convinced that was easier than using the regular forum notation, but whatever. :)
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wow! this is cool!! great job mitch.
$$ \mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\, +\, 6\mathrm{O}_2 \,\rightarrow\, 6\mathrm{CO}_2\, +\, 6\mathrm{H}_2\mathrm{O} /$$
Hmm?!? lol well, i think once we get the pattens right, it will be easier, like start and end with $$? i will practice and try it out later :)
thanks again!!
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Well, it doesn't make sense for reactions (I prefer UBBC exported from EBAS then, much less work with formatting, as EBAS does the formatting automagically), but even for simple math it does wonders.
$$ a_i = \frac {b_i + c_i} {1 + \sqrt{d^2 + e_i^2}} /$$
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Sweet! Thanks mitch!
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Good job Mitch , way to go
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$$ (\frac{\partial x}{\partial y})_z = S_om^et_hi^ng /$$
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Weee! Nice. Although I hate LaTeX.... but it is better then nothing I guess!
$$ A = \epsilon \time b \time c /$$
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hey, very cool!
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+i+%5Chbar+%5Cfrac%7B%5Cpartial%7D%7B%5Cpartial+t%7D+%5CPsi%28x%2Ct%29+%3D+%5Chat%7BH%7D+%5CPsi%28x%2Ct%29+%7D&hash=6a4b44f86e59ba7603645f3aa2408caa78b758a2)
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$$ dE = (dQ)_{rev} + dW /$$
Why do i get this "[img]http://www.forkosh.dreamhost.com/mimetex.cgi?" line at the start of each latex eqn/symbol i use???
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Part of the implementation. They are not hosted here.
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$$ e^{i\pi} + 1 = 0 /$$
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(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+X%5E2+%7D&hash=210caa0eac2f6f91ac3c58dabe746632c006e768)
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+%5Csum+%7D&hash=ee4061525870ca6a38e5b7a34b2175bd0834b928)
X^2 = (Observed - Expected)^2 / Expected
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+%28Observed+-+Expected%29%5E2+%7D&hash=6936f3a124ddf86bd22498df5b632d49b800b452)
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+%5Cdfrac%7B2%7D%7Bx%2B2%7D+%7D&hash=5d48db3d0ee71f6fd66df7e0a9e707e50e74bc29)
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+Expected+%7D&hash=dfaced3ebec5f3a9901c70a761c6924826c8e2c4)
$$ /dfrac{Observed - Expected}^2{Expected} /$$
Thank you
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How do I post my chemistry problem. I am using my mobile phone nokia3230
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Look for the "new topic" button in the correct subforum.
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$$ CH_{3}CHCH_{3}(CH_{2})_{3}CHCH_{3}(CH_{2})_{3}CHCH_{3}(CH_{2})_{3}CH(CH_{3})CH_{3} /$$
There we go... well, it was working...
Why does mine seem italicized?
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Agent-X: Use \text{} around the text you don't want italicized.
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(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+%5Ctext%7BCH_%7B3%7DCHCH_%7B3%7D%28CH_%7B2%7D%29_%7B3%7DCHCH_%7B3%7D%28CH_%7B2%7D%29_%7B3%7DCHCH_%7B3%7D%28CH_%7B2%7D%29_%7B3%7DCH%28CH_%7B3%7D%29CH_%7B3%7D%7D+%7D&hash=0db4e100605249a2c6c74dd879d2fbac3975cc32)
That works.
It would be nice if I could see it in the preview window, though.
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Can someone please tell me how i can type bond-lines using latex?
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Can someone please tell me how i can type bond-lines using latex?
Well, I mean a person could use hypens and equal signs. But that would only get so far. I know that certain chemistry programs will allow a person to output in tex formation. But I don't think this forum would accept the format.
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Simply you can use a free molecular-drawing software and export the documents in an image format (JPG, PNG or what you prefer), then host and insert in your message the image needed. I do so and it works great ;)
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hey, very cool!
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+i+%5Chbar+%5Cfrac%7B%5Cpartial%7D%7B%5Cpartial+t%7D+%5CPsi%28x%2Ct%29+%3D+%5Chat%7BH%7D+%5CPsi%28x%2Ct%29+%7D&hash=6a4b44f86e59ba7603645f3aa2408caa78b758a2)
Oh shiz. I recognize this equation....stupid Quantum Mechanics. Its gon be the death of my GPA.
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When I type:
$$ y=mx+b /$$
and then click preview, it doesn't work???
In other forums I would type, say for an integral
[math] \int\frac{1}{1-x^2}dx[/math]
is there a pdf file with all of the commands?
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Actually, it does seem to be working. When I clicked "preview' I got something else.
$$ \int\frac{1}{1-x^2}dx /$$
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Preview doesn't work.
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\[ \frac{1}{x^2 + y^2} \]
$$ \frac{1}{x^2 + y^2} /$$
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$$ Hello /$$
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$$ \Delta H /$$
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Is it possible for me to hide my text?
Like... the heading says 'click to reveal content (or something else)' and when you click on it the hidden text appears...like in the mathlinks forum?
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The internet use to use Rot 13 for things like that.
Srry serr gb hfr vg urer ng purzvpnysbehzf.pbz
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Gunax lbh, ohg vfag guvf whfg qrpbqvat ?
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Lrnu, ohg va n frafr vg npgf yvxr n fcbvyre gnt. Juvpu frrzf gb or jung lbh jrer trggvat ng.
</rot 13>
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Ok, I'm getting tired of having to refer to Wikipedia every time to decode this. It's consuming a lot of time. What does </rot 13> do? I can't seem to use it in my posts
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It doesn't mean anything, I just put it so you would know what I was doing.
More importantly, you have been doing this by hand!?? Just use this: http://www.rot13.com/
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Thanks for the link Mitch. I'm starting to like this now.
Oh... and please don't mistake my tone in my last post... I was getting totally stressed out doing it by hand
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I'm not exactly sure how you integrated LaTeX into the forum. You didn't use the Mimetex SMF-mod (http://custom.simplemachines.org/mods/index.php?mod=1111) for it due to the different tags and lack of latex button in the text editor menu, so I suppose you made something custom.
I tend to use LaTeX a lot, and the use of a button in the text editor menu to get the tags makes it much simpler to integrate into forum posts.
My suggestion:
- It might be easier for you to use the Mimetex SMF-mod (doesn't cause problems at forum updates compared to custom code).
- If not, could you please create a BBCode button for the LaTeX tags? You could probably use this mod (http://custom.simplemachines.org/mods/index.php?mod=621) for creating it.
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Practicing.
$$ y = mx +b /$$
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Practicing.
$$ y = mx + b /$$
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Determining whether what I am about to post will turn out properly. My apologies.
$$\begin {eqnarray} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \nonumber \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \nonumber \end{eqnarray} /$$
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$$\begin {equarray*} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{equarray*} /$$
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$$\begin {eqnarray*} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{eqnarray*} /$$
$$\begin {eqnarray} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{eqnarray} /$$
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My first question is how the authors were able to convert $ ln a_n /$ to $ (ln a_0 - \beta \varepsilon_n /$ , where an is the occupation number of the nth energy level,
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Sorry. Still practicing.
$$ \frac {dlnW} {da_n} = 0 /$$ for the Boltzmann distribution
$$ a_n = Ne^{\alpha} e^{- \beta \varepsilon_n} /$$
$$ ln a_n = ln a_0 - \beta \varepsilon_n /$$
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Still practicing.
$$ V_(total) = V^(partial,mol)_(A) n_A + V^(partial,mol)_(B) n_B /$$
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$$ V_{total} = V^{partial,mol}_{A} n_A + V^{partial,mol}_{B} n_B /$$
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Checking for errors.
$$ log \left (\frac {W} {W_{max}} \right) = -H log \left (\frac {h} {\frac {N} {2}} \right ) - T log \left (\frac {T} {\frac {N} {2}} \right ) /$$
$$ \alpha = \frac {(H - T)} {N} /$$
$$ H = \left (\frac {N} {2} \right ) (1 + \alpha ) /$$
$$ T = \left (\frac {N} {2} \right ) (1 - \alpha) /$$
$$ \frac {W} {W_{max}} = e^{-N \alpha ^{2}} /$$
$$ ln \left (\frac {W} {W_{max}} \right ) = - \left (\frac {N} {2} \right ) (1 + \alpha) ln (1 + \alpha) - \left (\frac {N} {2} \right ) (1 - \alpha) ln (1 - \alpha) /$$
$$ ln \left (\frac {W} {W_{max}} \right ) = - \left (\frac {N} {2} \right) (1 + \alpha) ln (1 - \alpha ^{2}) + N \alpha ln (1 - \alpha) /$$
$$ W = frac\ {N!} {\prod_{n} a_{n}!} /$$
$$ P_{dc} = \frac {W_dc} {\sum_{n} W_{n}} /$$
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$$ log \left (\frac {W} {W_{max}} \right) = -H log \left ( \frac {h} {\frac {N} {2}} \right ) - T log \left (\frac {T} { \frac {N} {2}} \right ) /$$
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$$ log \left (\frac {W} {W_{max}} \right) = -H log \left ( \frac {H} \left ({\frac {N} {2} \right )} \right ) - T log \left (\frac {T} \left ({\frac {N} {2} \right)} \right ) /$$
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$$ \Delta G = -RTlnK /$$
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Unuseful
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$$ \frac{d[A]}{dt} /$$
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test
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[img]http://www.forkosh.dreamhost.com/mimetex.cgi?{ \Delta{G} = \Delta{H} - T\Delta{S} /$$