Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: cell_491 on April 24, 2005, 08:39:01 PM
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heres an exmple of the type of problem im stumped on
what is the molality of a solid solution containing .125g of chromium and 81.3g of iron?
(the answer is .0296m but i have to show work and i dont know how to do it ???)
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First things first.
Molarity is moles/volume
Have you manipulated your given information into something that has units of either volume or moles?
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allright i got .0024mol of Cr and 1.455mol of Fe
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nvm i figured it out the equation is .125g/52g/(81.3g/1000)= .0296m
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MOLALITY - moles per kg of solvent