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Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Asalami on November 15, 2008, 10:59:17 AM

Title: Preparation of tetraphenyltin (IV)
Post by: Asalami on November 15, 2008, 10:59:17 AM

Hi, i have the general equation for the formation of tetraphenyltin (IV) as
SnCl₄ + PhMgCl =  SnPh₄.
But i was wondering :-
1)why do you have to first prepare SnCl₄.2(C2H5)₂O in the preparation of SnPh₄ and
2) Is it possible to make SnPh₂ from SnCl₂

Thanks