Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Kipper on December 16, 2008, 06:54:24 PM
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Hello,
This is actually a 3 part question. It is the last part that is giving me trouble.
Question C asks the following:
A 10.0 gram sample that is 30% C2H6 and 70% C4H10, by mass, is burned in excess oxygen. How much energy is released?
The answer for this is actually 4.6 x 10^2 kj but I can't figure out how they got this.
I'm not sure if the answers from (a) and (b) are relavant but I'll post them just in case:
a) calculate the enthalpy change for the complete combustion of
C4H10: answer is -2657 kj/mol
b) calculate the enthalpy change for the complete combution of C2H6:
answer -1428.4 kj/mol
If someone could enlighten me I would greatly appreciate it.
Thank you.
Kasey
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Dear Kipper;
Yes!, - The answers a) and b.) are very relevant to get the heat released.
Use the percentage(w/w) and show us your try, so we can tell you where you may go wrong.
Good Luck!
ARGOS++
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Well at first I confirmed that C2H6 was 3 grams and C4H10 was 7 grams and then I found the molar mass of each and calculated the moles per molecule.
For C2H6 I got 0.0997 moles and then for C4H10 I got 0.1204 moles. That's where I got stuck. I was thinking that because everything had to be in moles (usually) it was important for me to calculate them.
I then tried to calculate delta H for each one individual and then was thinking I could add the delta H's together but it didn't work out. Here's what I did:
C2H6:
delta H = -1428.4 x 0.0997 moles and then divided by current moles of 2
= -71.21 kj
C4H10
delta H = -2657 x 0.1204 and then divide by a mole of 1
= -319.90 kj
Adding them together gives -391 kj.
Am I completely off base in how I'm trying to solve this?
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Dear Kipper;
Please can you tell me why you divide? I don’t see any reason for.
Good Luck!
ARGOS++
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Funny I'm not sure why. I think I was trying to get the total answer into 1 mole, so I divided by the mole of 2 (which is based on the equation I had - equation showed 2 moles of C2H6).
However, if I don't divide at all and add the two amounts together I get the right answer of -4.6 x 10^2.
Yahoo!!!
Honestly I have no idea how I came up with the right answer but I did.
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Dear Kipper;
For this part there is no equation required at all, because you can use answers a.) and b.) instead.
So finally you did correct.
Good Luck!
ARGOS++