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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Zoloft on March 02, 2009, 09:38:45 AM

Title: Molar mass from boiling point and Kb...
Post by: Zoloft on March 02, 2009, 09:38:45 AM
Hey all, I'm slightly stuck on how to go about solving this.

"A solution prepared from 1.25 g of wintergreen (methyl salicylate) in 99.0 g benzene has a boiling point of 80.31 C. What is the molar mass of wintergreen? Boiling point of pure benzene is 80.10 C. Kb for benzene is 2.53C/m "


I know the answer is 152.12 g/mol of wintergreen, but I do not know how this answer was produced. Any directions or hints would be appreciated.

Title: Re: Molar mass from boiling point and Kb...
Post by: Zoloft on March 02, 2009, 09:51:57 AM
Never mind, I solved this.

:delta: Tb / kb = m

^my starting equation...and just solve for grams granted that molality is mol of methyl divided by Kg of benzene (solvent)