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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Zapper on March 03, 2009, 04:57:21 PM

Title: Need a little bit of help REDOX
Post by: Zapper on March 03, 2009, 04:57:21 PM

How do i write the products of three reactants  for a redox equation?

KMnO4(-) + NaHSO3(-) + H2SO4 => ?

Please help me understand how to write it and why it works that way.

Title: Re: Need a little bit of help REDOX
Post by: Arkcon on March 03, 2009, 06:27:29 PM

Well, to help you try to figure it out on your own, since you've been told this is a Red-Ox reaction, can you take a stab at what is reduced, and what is oxidized?  It's a little daunting, at first, doing it that way, but you'll be better off at exam time.

Title: Re: Need a little bit of help REDOX
Post by: Zapper on March 03, 2009, 08:31:00 PM

I think i figured it out

2(5e(-)+ 8H(+) + MnO4(-) >> Mn(+2) + 4H2O)
5(H2O + HSO3(-) >> SO4(-2) + 3H(+) + 2e(-))

= 2MnO4(-) + 5HSO3(-) + 8H(+) >> 5SO4(-2) + 2MN(+2) + 3H2O

Title: Re: Need a little bit of help REDOX
Post by: Borek on March 04, 2009, 03:24:25 AM

Check hydrogen.