Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Aznhmonglor on March 08, 2009, 09:29:36 PM
-
Can anyone explain to me what is a trace acid or take a look at this problem? Not sure what it wants.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.webassign.net%2Fuserimages%2Fkasandbe%40ncsu%2FCH223_fall_02%2Fch223_ssii03_ex2be.gif&hash=8efb6a9d50186d072d9ef4953a3ec62dbab90259)
-
I'd assume it just means very dilute.
-
Protonate the double bond Oxygen then?
-
That's what I'd do, but the major product may just end up being your reactant anyway?
-
This question is confusing.
-
Any nucleophilic sites you see that could attack a protonated carbonyl?
-
Trace is just a different word for catalytic amount
-
Trace means very small amount, which can not be determined exactly.
-
What would small amounts of acid do to my reactant?
-
Can anybody help? I tried this and still couldn't get it right, I thought the OH would form a bond with the Carbonyl group to form a ring but was wrong.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fimg.photobucket.com%2Falbums%2Fv470%2Fazn_hmong_lor%2Funtitled-1.jpg&hash=c7603f6366918e91ba5fce3bc8bdf271739f2356)
-
You're right, but something has to happen to the carbonyl - you aren't displacing a proton/hydrogen.
-
would the carbonyl group turn into an alcohol? double bond O turns into OH?
Something like this?
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fimg.photobucket.com%2Falbums%2Fv470%2Fazn_hmong_lor%2Funtitled-2.jpg&hash=51792daf99261d1238c6d5da16ea1aac3e3b968f)
-
Can anybody still help me on this? Its bothering me so bad. I know what trace acid is now. It works the same way as any acid would but with this reactant, I dont know where to start. Maybe the double bond O is protonated to form this:
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fimg.photobucket.com%2Falbums%2Fv470%2Fazn_hmong_lor%2Funtitled-6.jpg&hash=c74b9551b8e13901f8469335d801ed6af6c87d53)
After that can the two OH groups come together to form a cyclic compound?
-
Okay that didnt work out. This was incorrect.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fimg.photobucket.com%2Falbums%2Fv470%2Fazn_hmong_lor%2Funtitled-7.jpg&hash=47fd1a0d12c76f29b6ec0dec4e5dab94a0aa5d6e)
Any ideas?
-
would the carbonyl group turn into an alcohol? double bond O turns into OH?
Something like this?
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fimg.photobucket.com%2Falbums%2Fv470%2Fazn_hmong_lor%2Funtitled-2.jpg&hash=51792daf99261d1238c6d5da16ea1aac3e3b968f)
That would be my answer. Do you know why?
-
I think that all of you are mistaked in the answer.
Dehydratation, isomerization = a,b-insaturated aldehyde
-
Might he be just a purification process??? It can't be dehydration reaction cuz the acid is too dilute!!! It might be a hydration reaction or maybe a rearrangement reaction which seems unlikely!!! I'd still say him to be a purification reaction!!!
Lutesium...
-
My two cents:
The aldehyde is by far the most reactive group here so would get protonated before the alcohol. The alcohol is tethered to the cyclic ring and one of its lone pair of electrons will be sat right next to an activated aldehyde. The ring would snap shut as 5 membered cyclic hemiacetals are stable (wiki hemiacetals).
-
Might he be just a purification process??? It can't be dehydration reaction cuz the acid is too dilute!!! It might be a hydration reaction or maybe a rearrangement reaction which seems unlikely!!! I'd still say him to be a purification reaction!!!
Lutesium...
It never said the acid was in water.
-
Might he be just a purification process??? It can't be dehydration reaction cuz the acid is too dilute!!! It might be a hydration reaction or maybe a rearrangement reaction which seems unlikely!!! I'd still say him to be a purification reaction!!!
Lutesium...
It never said the acid was in water.
Ok but I really don't see a reaction in here that'd occur with trace amount of acid here!!! Dehydrative cyclization (to the BenzoPentanone) with the phenolic -OH group being eliminated which is so unlikely!!!
Lutesium...
-
trace acid catalyses the ring closing reaction, ill give the mechanism as well:
Can you see how the acid is acting as a catalyst?
-
Ok that's possible but with trace amounts of substrate!!! If the substrate is 1kg / lt trace amounts of acid won't do anything if this reaction is desired long reflux times must also be considered!!!
Lutesium...
-
Ok but I really don't see a reaction in here that'd occur with trace amount of acid here!!! Dehydrative cyclization (to the BenzoPentanone) with the phenolic -OH group being eliminated which is so unlikely!!!
What phenolic -OH? All I can see is regular old aliphatic hydroxyl groups....
S
-
Ok ok I didn't pay attention to the molecule!!! Of course he is not a phenolic -OH he is just an aliphatic -OH...
Lutesium...